X plus 1 whole cube Formula

 What is (x+1)3 expand Formula

The (x+1)3 expand formula is a special type of algebraic identity 

(x + 1)3 Formula

Basic:

The (x+1)3 formula is a special type of algebraic identity. This formula is used to solve a cube of binomial the type (x+1)3. The (x+1)3 formula can be derived by using the parent (a+b)3 formula or the expansion of (x+1)3 can be done by multiplying (x+1) thrice. To simplify the (x+1)3 formula we just multiply and then combine the like terms and the like variables together. Finally, we will arrange our expression according to the increasing order of the exponential power. (x+1)3 = x3 + 3x3+ 3x + 1 The expansion of formula (x+1)3= (x+1)(x+1)(x+1)

Proof of (x+1)3 Formula

The (x+1)3 formula can be derived or proved by multiplying (x + 1) thrice,

(x+1)3 = (x+1)(x+1)(x+1)

(x+1)3 = (x2+ x + x + 1) (x + 1)

(x+1)3 = (x + 1) [x2+ 2x + 1]

(x+1)3 = x3 + 2x2 + x + x2+ 2x + 1

(x+1)3 = x3+ 3x2+ 3x + 1

Therefore, (x+1)3 = x3 + 3x2 + 3x + 1

Examples on (x+1)3 Formula

Example 1: Find the expansion of (y+1)3.

Solution:

Using

(x+1)3 = x 3 + 3x2 + x + 1

Let

x=y

(y+1)3= y3+ 3y2 + y + 1

Answer: y3+ 3y2+ y + 1

Example 2: Factorise 1+64a3+12a +48a2

Solution:

1+64a3+12a +48a2

Using the (x+1)3 =x 3 + 3x2 + x + 1

= 13 + (4a) 3 + 12a(1+4a)

= 13+(4a)3 + 3(4a)2 +3(4a)

= (1+4a)3= (1+4a) (1+4a) (1+4a)

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X plus 1 whole cube Formula
X plus 1 whole cube Formula

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Frequently Asked Questions on X plus 1 whole cube Formula

X plus 1 whole cube Formula can be defined as a special type of algebraic identity, and solved as The (x+1)3 formula can be derived by using the parent (a+b)3 formula or the expansion of (x+1)3 can be done by multiplying (x+1) thrice.

(x+1)3 = x3 + 3x2 + 3x + 1