NCERT Class 4 Maths Chapter-6 The Junk Seller

NCERT Solutions for Class 4 Maths Chapter-6

NCERT textbook consists of Chapter 6 The Junk Seller which consists of lots of questions in exercise as well as inside the textbook, our experts solved all the questions asked in The Junk Seller as per the CBSE guideline.

What are you going to learn in Chapter 6 The Junk Seller?

Do you what is Kabariwali? Hopes lots of you heard this name Chapter 6 The Junk Seller is a true story told by Kiran– a woman who sells junk. who has a junk shop in Patna? A very beautifully explained story cum maths application which starts with the introduction of kiran who says I studied in a Hindi medium school in my village near to my house. My father wanted girls to study like boys. I loved subjects like Hindi and Science, but I don’t like Maths. Today Maths is most useful for my work. I could never imagine this in school. And this chapter starts with the fundament use of math in small businesses and why you are reading all these concepts you will understand in Chapter 6 The Junk Seller. The kind of question you are going to solve in this chapter is How much will Dinu pay for 63 kg of plastic? Answer- The rate of 1 kg plastic is Rs 12. So the cost of 63 kg plastic will be Rs 12 × 63. Remember, you.

Download step by step explanation of NCERT Solutions for Chapter 6 The Junk Seller

Q1:

• What about you? Do you also find Maths difficult?
• What is the most difficult thing in your Maths books?
• What do you think is the easiest lesson?

Answer:

• No, I don’t find maths difficult.
• The most difficult thing in maths book is Division.
• The easiest lesson is addition. Q2: Find out: how much for a cup of tea?

Ask people and find out the cost of a cup of tea

• at a tea stall
• at a hotel

Answer:

• At a tea stall a cup of tea costs Rs 15.
• At a hotel a cup of tea costs Rs 25.

Q3: If a person who runs a tea stall earns Rs 30 in a day, how much will he earn in 10 days?____________and in a month?____________How did you get the answer? Discuss.

Answer:

If a person who runs a tea stall earns Rs 30 in a day then in 10 days he will earn = Rs 30x10 = Rs 300.

A month has 30 days. If the person earns Rs 30 in a day then in 30 days he will earn= Rs 30x30 = Rs 900.

Q4: Hariya and Babu want to buy a handcart for Rs 300.

Who has to pay back more — Hariya or Babu?_________________

Answer:

If Hariya has to pay Rs 51 every month for 6 months then, The total amount paid by Hariya = Rs 51x6 = Rs 306

Thus, Hariya has to pay Rs 306 in 6 months whereas Babu has to pay Rs 360 after 6 months. So that means Babu has to pay more.

Q5: I have 9 rickshaws of my own. I give the rickshaws on rent. each for Rs 20 a day. On Sundays I do not take any money for them.

• In a week how much does Kiran earn from one rickshaw? Answer:

If Kiran doesn’t give Rickshaw on Sundays then in a week he gives the rickshaw on rent for 6 day. Rent earned each day from one Rickshaw = Rs 20

Rent earned from one rickshaw in 6 days = Rs 20 x 6 = Rs 120 Thus in a week Kiran earns Rs 120 from one Rickshaw.

Q6: Do it mentally and write the answers. 2 × 6 =

20 × 6 = _____________

2 × 60 = _____________

3 × 42 = _____________

4 × 80 = _____________

4 × 81 = _____________

9 × 25 = _____________

31 × 9 = _____________

Answer:

12

120

We do it in the following manner: 2 times 6 is 12. 20 times 6 is 120.

120

126

We do it in the following manner: 3 × 40 = 120 Also, 3 × 2 = 6

So, 120+6= 126

32 We do it in the following manner: 4 times 8 is 32.

4 times 80 is 320.

324

We do it in the following manner: 4 × 80 = 320 Also, 4 × 1 = 4

So, 320+4= 324

225 We do it in the following manner: 9×20 = 180 Also, 9 × 5 = 45

So, 180+45 = 225

279 We do it in the following manner: 30 × 9 = 270

Also, 1 × 9 = 9

So, 270+09= 279

Q7: Look up the rate list to see today’s rates. Help Kiran to find out the cost of the junk.

• How much will Kiran pay for 31 kg newspaper? 1 kg newspaper costs Rs 5. 30 kg cost Rs 5 × 30 = Rs

150. So, for 31 kg she pays Rs .

• How much will Kiran pay for 42 kg newspaper?

• Also find the cost of: (a) 22 kg of plastic (b) 23 kg of waste paper (c) 12 kg of iron

Can you do this without writing? Guess the total money Kiran will pay to the junk collectors. Will it be

— More than 600? — Less than 600? Answer:

1 kg newspaper = Rs 5

31 kg newspaper = Rs 5 × 31 = Rs 155 Procedure:

Step1: 5 × 30 = 150

5 × 1 = 5

So, Rs 150+5 = Rs 155.

42 kg newspaper = Rs 5 × 42= Rs 210 Procedure:

Step1: 5 × 40 = 200

5 × 2 = 10

So, Rs 200+10 = Rs 210

(a) 1 kg plastic costs = Rs 10

Cost of 22 kg plastic = 22 × Rs 10 = Rs 220 Procedure:

Step 1: 22 × 1 = 22

22 × 10 = 220

(b) 1 kg waste paper costs = Rs 4

23 kg waste paper will cost = Rs 4 × 23 = Rs 92 Procedure:

Step 1: 4 × 20 = 80

Step 2: 4 × 3 = 12 So, Rs 80+12 = Rs92

(c) 1 kg iron costs = Rs 12

12 kg iron will cost = Rs 12 × 12 = Rs 144

Add the numbers in the box 100+20+20+4=144

Total money paid to junk collectors will be = Rs 155 + Rs 210 + Rs 220 + Rs 92 + Rs 144 = Rs 821 155+210+220+92+144=821

So, the total money paid to the junk seller is more than Rs 600.

Q8: Kiran bought 1 kg plastic for Rs 10, but sold 1 kg plastic for Rs 12. How much money does she earn on selling 1 kg of plastic? Rs______So, how much money does she earn for 63 kg? Rs______

Answer:

1 kg plastic costs = Rs 10

Selling price of 1 kg plastic = Rs 12

On selling 1 kg plastic we get a profit of = Rs (12 − 10) = Rs 2 On selling 63 kg plastic we get a profit of = Rs 2 × 63 = Rs 126 Procedure:

Step 1: 2 × 60 = 120

Step 2: 2 × 3 = 6

Rs 120+6= Rs 126

Therefore, On selling 63 kg plastic Kiran will earn Rs 126. Q9: How much money will Dinu pay for 32 kg iron?

Kiran buys 1 kg of iron for Rs 12 but sells it for Rs 14. How much does she earn when she sells 32 kg iron? Rs

Answer:

1 kg iron costs = Rs 14

32 kg iron costs = Rs 14 × 32 = Rs 448

We do it like this:

300 + 120 + 20+8 =448

So, for 32 kg iron Dinu needs to pay Rs 448. For Kiran the cost of 1 kg iron = Rs 12

But, the selling price of 1 kg iron = Rs 14

On selling 1 kg iron the profit earned = Rs (14 − 12) = Rs 2 On selling of 32 kg iron the profit earned = Rs 2 × 32 = Rs 64 Procedure:

Step 1: 2 × 30 = 60

Step 2: 2 × 2 = 4

So, 60+4= 64

Therefore, on selling 32 kg iron Kiran earns Rs 64.

Q10: I bought 1 kg newspaper for Rs 5, but sold it for Rs 6. How much money did I earn by selling 152 kg of newspaper?__________

Answer:

1 kg newspaper costs = Rs 5

Amount received on selling 1 kg of newspaper = Rs 6

On selling 1 kg newspaper the profit earned = Rs (6 − 5) = Re 1

On selling 152 kg newspaper the profit earned = Re 1 × 152 = Rs 152 On selling 152 kg of newspaper Kiran the total amount earned Rs 152.

Q11: How much money will Dinu pay for 4 kg brass? Guess the answer first. Answer:

Cost of 1 kg brass = Rs 180 Cost of 4 kg brass = Rs 4×180 = Rs 720 We will do it as follows:

400+320 = 720Thus, Dinu will pay Rs 720 for 4 kg brass. Q12: First guess the answer and then calculate:

(a) 37 × 18 =

(b) 45 × 24 =

(c) 69 × 52 =

(d) 77 × 55 =

(e) 142 × 5 =

(f) 382 × 3 =

(g) 2 × 175 =

(h) 4 × 206 =

Answer:

(a) Add the numbers in the box 300 + 240+ 70+56=666

(b) Add the numbers in the box 800+100+160+20=1080

(c) Add the numbers in the box 3000+450+120+18=3588

(d) Add the numbers in the box 3150+350+350+35=4235

(e) Add the numbers in the box 500+200+10=710

(f) Add the numbers in the box 900+240+6=1146

(g) Add the numbers in the box 200+140+10=350

(h) 800+24=824

Q13: Later she paid Rs 919 to the junk collectors. When she sold the junk she got these notes and coins from Dinu.

Now you make a record in her diary. Find out how much she earned this time.

Answer:

We do it as follows:

5 notes of 100 rupee 5 × 100 = Rs 500

1 note of 50 rupee 1 × 50 = Rs 50

18 notes of 10 rupee 18 × 1 = 18

18 × 10 = Rs 180

9 notes of 20 rupee 9 × 2 = 18

9 × 20 = Rs 180

28 coins of 5 rupee 20 × 5 = 100

8 × 5 = 40

100+40=140

28×5 = Rs 140

Money I got = Rs 500 + Rs 50 + Rs 180 + Rs 180 + Rs 140 = Rs 1050 500+180+180+140=1050

Money I earned = Rs 1050 − Rs 919 = Rs 131