(a) BF3 > BCl3 > BBr3
(b) BF3 = BCl3 > BBr3
(c)BF3 < BCl3 < BBr3
(d) BBr3 > BF3 > BCl3
(c)
Sol. 2p of Boron will overlap with 2p of F most efficiently. Hence, BF3 is having the least tendency to accept the lone pair from an external source.
(a) BF3 > BCl3 > BBr3
(b) BF3 = BCl3 > BBr3
(c)BF3 < BCl3 < BBr3
(d) BBr3 > BF3 > BCl3
(c)
Sol. 2p of Boron will overlap with 2p of F most efficiently. Hence, BF3 is having the least tendency to accept the lone pair from an external source.