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Derive an expression for work done by the gas in an Isothermal process.

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Let P1V1
​
T be initial pressure, volumes and temperature.
Let expand to volume V2 ​& pressure reduces to P2
​
& temperature remain constant. Then, work done

W=∫dW
W=∫​PdV
PV=RT
W=RT/VdV
RT[InV] RT[InV2−InV1] W=RTInV2/V1

W=2.303RTlog10V2/v1

OR wkt,

p1/p2=v2/v1

w= 2.303RTlog10P1/P2

Final answer:
Derived

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