Add (𝟏𝟓𝒙𝒚𝟐𝒛 + 𝟏𝟒𝒙𝒛 + 𝟑𝒙𝒚 − 𝟏𝟎𝒚𝟐𝒙)𝒂𝒏𝒅(𝟑 + 𝒙𝒚𝟐𝒛 + 𝒙𝒚𝟐 + 𝒙𝒚)using the column method.
Solution:
In the column method, write the expressions, such that the like terms are arranged in the same column.
15𝑥𝑦2𝑧 | +14xz | +3xy | -10𝑦2𝑥 | |
𝑥𝑦2𝑧 | +xy | + 𝑥𝑦2 | +3 |
In the above arrangement, there is no term under 14xz as there is no term in the second expression with the same variables. Also, 10𝑦2𝑥 𝑎𝑛𝑑 𝑥𝑦2 have the same variables with the same exponents. Hence they are like terms.
Now adding the like terms,
15𝑥𝑦2𝑧 | +14xz | +3xy | −10𝑦2𝑥 | |
𝑥𝑦2𝑧 | +xy | +𝑥𝑦2 | +3 | |
16𝑥𝑦2𝑧 | +14xz | +4xy | −9𝑥𝑦2 | +3 |
Thus, (15𝑥𝑦2𝑧 + 14𝑥𝑧 + 3𝑥𝑦 − 10𝑦2𝑥) + (3 + 𝑥𝑦2𝑧 + 𝑥𝑦2 + 𝑥𝑦) = 16𝑥𝑦2𝑧 − 9𝑥𝑦2 + 4𝑥𝑦 + 14𝑥𝑧 + 3