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A particle of mass m and charge q is thrown at a speed u against a uniform electric field E. How much distance will it travel before coming to momentary rest?

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Mass of particle = m
Charge of particle = q
Electric field = E
Initial velocity = u
Force experienced by particle = qE
Deceleration, a = force/mass = qE/m (as electric field is opposing factor)
Final velocity, v = 0
Distance travelled before coming to momentary rest = s
v²=u²-2as
0=u²-2(qE/m)s
s=(mu²/2qE) units

Final Answer:

Hence, the distance travelled before coming to momentary rest is (mu²/2qE )units.

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