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A cyclotron’s oscillator frequency is 10 MHz . What should be the operating magnetic field for accelerating protons? If the radius r of its ‘dees’ is 60 cm, calculate the kinetic energy (in MeV ) of the proton beam produced by the accelerator.

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Given: Oscillator frequency () = 10 MHz, Radius of dees (r) = 60 cm
To find: Kinetic energy of proton beam produced by the accelerator, Magnetic field
Solution:
Magnetic field
Final answer:
Hence, the correct answers are, Kinetic energy = 7.4 MeV, Magnetic field = 0.66 T

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