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(1) Latent heat of steam is 540 cal/gm. Express this in SI units. (2) A liquid has a mass of 200 gm and a specific heat capacity of 0.8cal/gm/°C. Find water equivalent of the liquid.

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(1) Given: Latent heat of steam = 540 cal/gm
To calculate: Latent heat in SI units
Solution: 1 cal = 4.18 J/kg
540 cal/gm = 540 X 4.18 X 1000 J/kg = 2257200 J/kg

(2) Given:Mass of liquid = 200gm, Specific heat capacity of liquid = 0.8 cal/gm/°C
To calculate: Water equivalent of the liquid
Solution:Water equivalent is defined as product of mass and specific heat
Water equivalent = mass X specific heat = 200gm X 0.8 cal/gm/°C = 160 cal/°C

Final answer:
Hence, correct answers are: Latent heat of steam = 2257200 J/kg
Water equivalent = 160 cal/°C

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