Which one of the following has the maximum number of atoms?

Explanation:

Specie having maximum number of moles will have maximum number of atoms because number of atoms = moles × Avogadro number

Number of moles = mass / atomic mass

1. Moles of 1 g of Mg(s) = 1/24 = 0.04
2. Moles of 1 g of O₂(g) = 1/16 = 0.0625
3. Moles of 1 g of Li(s) = 1/7 = 0.143
4. Moles of1 g of Ag(s) = 1/108 = 0.0092

Final Answer:

Option C is correct i.e 1 g of Li(s) has maximum number of atoms