(i) x + y = 5, 2x + 2y = 10

(ii) x – y = 8, 3x − 3y = 16

(iii) 2x + y = 6, 4x − 2y = 4

(iv) 2x − 2y – 2 = 0, 4x − 4y – 5 = 0

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 i)  x + y = 5
         2x + 2y = 10
We get,
Variable
Therefore these pair of lines have infinite number of solutions and
x + y = 5
x = 5 - y
putting y = 1,2,3 we get,
x = 5 -1 = 4
x = 5 - 2 = 3
x = 5 - 3 = 2

x 4 3 2
y 1 2 3

variable

x 4 3 2
y 1 2 3

(ii) x – y = 8, 3x − 3y = 16

Variable

Therefore, these linear equations are intersecting each other at one point and thus have only one possible solution.
Hence,the pair of linear equations is inconsistent.

(iii) 2x + y = 6, 4x − 2y = 4

We get,

variable

Therefore, these linear equations are intersecting each other at one point and thus have only one possible solution.
Hence,the pair of linear equations is consistent

2x + y - 6 = 0

y = 6 - 2x

x 0 1 2
y 6 4 2

Variable

x 1 2 3
y 0 2 4

Variable

(iv) 2x − 2y – 2 = 0, 4x − 4y – 5 = 0

We get,

variable

Therefore, these linear equations are parallel to each other and have no possible solution,
Hence,the pair of linear equations is inconsistent.



 

 

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