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A cyclotron's oscillator frequency is 10 MHz . What should be the operating magnetic field for accelerating protons? If the radius r of its 'dees' is 60 cm, calculate the kinetic energy (in MeV ) of the proton beam produced by the accelerator.

Given: Oscillator frequency ( ) = 10 MHz, Radius of dees (r) = 60 cm

To find: Kinetic energy of proton beam produced by the accelerator,  Magnetic field

Solution:

Magnetic field

Hence, the correct answers are,  Kinetic energy = 7.4 MeV, Magnetic field = 0.66 T

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