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The correct solution is option C i.e.the maximum no.of e–present in K, L and M shells are 2,8 and 18 respectively.
The maximum no.of e– in a shell/orbit, having principal quantum number (n) =2n2.
So, K shell whose principal quantum no., n=1, maximum no.of e– =2(1)2=2
Similarly, L shell having n=2, maximum no.of e– =2(2)2=8 &
M shell having n=3, maximum no.of e–=2(3)2=18.
Hence, the correct answer is choice C.
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