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The correct solution is option C i.e.the maximum no.of epresent in K, L and M shells are 2,8 and 18 respectively.

The maximum no.of e in a shell/orbit, having principal quantum number (n) =2n2.

So, K shell whose principal quantum no., n=1, maximum no.of e–  =2(1)2=2

Similarly, L shell having n=2, maximum no.of e =2(2)2=8 &

M shell having n=3, maximum no.of e=2(3)2=18.

Hence, the correct answer is choice C.

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