(i) Tetrahydroxidozincate (II) 

(ii) Potassium tetrachloridopalladate(II) 

(iii) Diamminedichloridoplatinum(II) 

(iv) Potassium tetracyanidonickelate(II) 

(v) Pentaamminenitrito-O-cobalt(III) 

(vi) Hexaamminecobalt(III) sulphate

(vii) Potassium tri(oxalato)chromate(III)

(viii) Hexaammineplatinum(IV)

(ix) Tetrabromidocuprate(II)

(x) Pentaamminenitrito-N-cobalt(III)

 

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Ans: (i) Tetrahydroxidozincate (II) = [Zn(OH)4]-2

Explanation: Tetrahydroxi means 4 hydroxide ions with zinc in +2 oxidation state. Hydroxide ions have a negative charge of -1 , so balancing the overall charge of the coordination compound to be zero we get the formula as : [Zn(OH)4]-2

(ii) Potassium tetrachloridopalladate(II) = K3[PdCl4].

Explanation: Tetrachlorido means 3  Chloride ions each having a negative charge. Platinum is in +2 state. Balance overall charge as 0, no. Of potassium ions are 3. Formula: K3[PdCl4].

(iii) Diamminedichloridoplatinum(II) = [Pt(NH3)Cl2]2+

Explanation: Diammine means 2 ammonia molecules, dichlorido means 2 chloride ions , platinum in +2 state. Formula: [Pt(NH3)Cl2]2+

(iv) Potassium tetracyanidonickelate(II)= K2[Ni(CN)4].

Explanation: tetracyanido means 4 cyanide ions each with a unit negative charge and nickel atom with +2 state. Formula: K2[Ni(CN)4].

(v) Pentaamminenitrito-O-cobalt(III) = [Co(ONO)(NH3)5]+2

Explanation: penataammine means 5 ammonia molecules, nitrito-O means nitrate ion which is bonded to central atom via oxygen and cobalt in +3 state. Formula: [Co(ONO)(NH3)5]+2

(vi) Hexaamminecobalt(III) sulphate =[Co(NH3)6]2(SO4)3

Explanation: hexaammine means six ammonia molecules and cobalt in +3 state. Sulphate have a negative charge of-2. Balance overall charge as 0. Formula: [Co(NH3)6]2(SO4)3

(vii) Potassium tri(oxalato)chromate(III) = K3[Cr(C2O4)3].

Explanation: trioxolato means 3 oxolate ions and chromium in +3 state. Balance overall charge as 0. Formula: K3[Cr(C2O4)3].

(viii) Hexaammineplatinum(IV) = [Pt(NH3)6]4+

Explanation: hexaammine means 6 neutral ammonia molecules and platinum in+4 state. Balance overall charge as 0. Formula: [Pt(NH3)6]4+

(ix) Tetrabromidocuprate(II)= [Cu(Br)4]2-

Explanation: tetrabromido means 4 bromide ions with a unit negative charge each and copper in +2 state. Balance overall charge as 0. Formula: [Cu(Br)4]2-

(x) Pentaamminenitrito-N-cobalt(III) = [Co(NO2)(NH3)5]2+

Explanation: pentaammine means 5 neutral ammonia molecules, nitrito-N means nitro group bonded to central atom via the lone pair of electron of nitrogen and cobalt in +3 state. Balance overall charge as 0. Formula: [Co(NO2)(NH3)5]2+

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