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(i) 135 and 225
(ii) 196 and 38220
(iii) 867 and 255
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(i) 135 and 225
We know that,
= 225>135
Applying Euclid’s division algorithm
225 = 135 ×1+90
Here remainder = 90,
So, Again Applying Euclid’s division algorithm
135 = 90×1+45
Here remainder = 45,
So, Again Applying Euclid’s division algorithm
90 = 45×2+0
Remainder = 0,
Hence ,
HCF of (135, 225) = 45
(ii) 196 and 38220
We know that,
38220>196
So, Applying Euclid’s division algorithm
38220 = 196×195+0
Remainder = 0
Hence,
HCF of (196, 38220) = 196
(iii) 867 and 255
We know that,
867>255
So, Applying Euclid’s division algorithm
867 = 255×3+102
Remainder = 102
So, Again Applying Euclid’s division algorithm
255 = 102×2+51
Remainder = 51
So, Again Applying Euclid’s division algorithm
102 = 51×2+0
Remainder = 0
Hence,
(HCF 0f 867 and 255) = 51
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