( ωt + kx + 0.57 )m and y2 = acos ( ωt + kx )m, where x is in metre and t in second. The phase difference between them is

A: 0.57 radian

B: 1.0 radian

C: 1.25 radian

D: 1.57 radian

 

Report
Question

Explanation:

The twwo waves can be written as 

y1=asin(t+kx+0.57)

y1=acos(t+kx)

y1=asin(t+kx+0.57+2)

So the phase difference is 

=2-0.57

=1.57-0.57

=1.00

Final Answer:

The correct option is (B).

solved 5
wordpress 4 mins ago 5 Answer 70 views +22

Leave a reply

 Prev question

Next question