Two different dice are tossed together. Find the probability: (i) of getting a doublet (ii) of getting a sum 10, of the number on the two dice.

The term "probability" purely refers to the likelihood of the occurrence of an event.

P( E) = Number of favorable outcomes / Total number of possible outcomes

Now, the total number of possible outcomes when two dice are tossed at once is 6 x 6 = 36.

(i) Getting a doublet:

The favorable outcomes are { ( 1. 1), (2, 2), (3, 3), (4, 4), (5, 5), (6, 6) }.

Number of favorable outcomes

So, the probability is

P( doublet) = 6 / 36

= 1 / 6

(ii) Getting a sum10:

The favorable outcomes are { (4, 6), (5, 5), (6, 4) }.

Number of favorable outcomes= 3

So, the probability is

P ( sum = 10) = 3 /36

= 1 / 12

Hence, the probabilities are

(i) P( doublet) = 1 / 6

(ii) P ( sum = 10) = 1 /12