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Given the thickness ( t) = 0.802m
Least count ( L.C) = 0.001cm
Now, the error in measuring the thickness will be
(t ± L.C) = ( -0.802 ± 0.001)
Now, the percentage error will be
= 0.001/0.802 x 100%
= 0.1246%
= 0.125%
Thus, option (A) is correct.
Hence, option (A) is correct..
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