There are two examination rooms A and B . If 10 candidates are sent from A to B , the number of students in each room is the same.

Therefore;

x + 20 =2( y – 20 )

⇒ x + 20 =2y – 40

⇒ x – 2y =- 60…(ii)

From equation(i);

x – 10 = y + 10

x – y =20

x = 20 + y…(iii)

Substituting the value of x in equation(ii);

x – 2y =- 60

20 + y -2y = - 60

20 - y = - 60

- y = 60 – 20

- y = - 80

y = 80

Therefore;

x = 20 + y

x = 20 _80

x = 100

Therefore, the number of students in room A are and in room B are .

Hence, we concluded that the number of students in room A are and in room B are