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The orbital velocity of an artificial satellite in a circular orbit just above the earth's surface is V 0 . The orbital velocity of a satellite orbiting at an altitude of half of the radius, is:
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The velocity of the satellite
V=√(GM/(R+h)) where G is the gravitational constant M is the mass of earth,R is the radius.h is the height of the satellite.
As the satellite is above the earth surfaceh=0
V=√(GM/R)
When the satellite is orbiting at a height h=R/2
V=√(GM/(R+R/2))
⇒V_ =√(2GM/3R)
⇒V_ =√(2/3) v0
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