The half life of a radioactive material is ‘T’ second. If 80% of the sample decay after time ‘t’ second, then find out the time when 90% of the sample decay.

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Let t’ be the time taken to decay 90% of the sample
According to law of radioactive decay,
N=N0e-t( N is the number of sample left, and N0is the number of sample at the beginning)
 lnN0N=t (  is decay constant which is, =ln2T)
According to the question, 80% of the sample decay after time ‘t’ second, so 20% of the radioactive sample is left after ‘t’ second. Hence,
ln10020=ln2Tt   (=ln2T)
ln5=ln2Tt
t=ln5ln2T
When 90% of the sample is decayed, then 10% of the radioactive sample is left. Hence time taken is t’,
ln10010= ln2Tt'
ln10=ln2Tt'
t'=ln10ln2T
=ln(52)ln2T
=ln5+ln2ln2T
=ln5ln2T+T
=t+T

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Hence, the correct option is A, i.e. T+t
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