The 17th term of an AP exceeds its 10th term by 7. Find the common difference.

Tenth and seventeenth terms of this AP can be given as follows:

a₁₀ = a + 9d

a₁₇ = a + 16d

Subtracting 10th term from 17th term, we get;

a + 16d – a – 9d = 7

7d = 7

d = 1