Sum of the areas of two squares is 468m2. If the difference of their perimeters is 24m, find the sides of the two squares

Let the first square's side be ‘ a ‘ m and the second square's side be ‘ A ‘ m.

The first square's area is equal to a²sqm.

The second square’s area is equal to A²sqm.

Perimeters will be 4 and 4A.

Given 4A – 4a = 24

A – a = 6 – ( 1 )

(1), A = a + 6A

From

When is substituted for in (2), we get

Hence, the first square's side is 12 meters long, while the second square's side is 18 meters long.