Substance having maximum number of moles is:

Explanation:

A. Number of moles (n)= mass/molar mass

n=90 g / 18 g/mol

n= 5 mol

B. ideal gas equation is PV=nRT

n=PV/RT

n= (1 atm)(112 L)/( 8.314 kJ/K-mol)(298 K)

n= 0.045 mol

C. n= mass/molar mass

n= 24 g /4 g/mol

n= 6 mol                       

D. 6.022 × 10²⁴ molecules are present in 1 mol of CO₂.

1 molecule is present in 1 / 6.02×  10²⁴ mol

Thus, 3.01 ×  10²⁴ molecules are present in 3.01 ×  10²⁴ (1 / 6.02× 10^24 mol)

= 0.5 mol