Solve x2 + 3x + 2 = 0

Given,

x² - 3x + 2 = 0

⇒ x²- (1+2)x + 2 = 0, middle term factor

⇒ x²– x - 2x + 2

⇒x(x-1) - 2(x-1) = 0

⇒(x-1) (x-2)=0

Since the product of two numbers is zero if at least one of them is zero.

Either, x-1=0⇒x=1

Or, x - 2 = 0 ⇒ x = 2

Solutions are x = 1, 2

Hence, the solutions of the given quadratic equation are x = 1, 2