Solve the following pair of linear equations by the substitution and cross-multiplication methods:

Substitution Method:

8x + 5y = 9 … (i)

3x + 2y = 4 … (ii)

From equation (ii),we get

x = … (iii)

Substituting this value in equation (i), we obtain

8() + 5y = 9
32-16y+15y =27
-y =-5

Y = 5 … (iv)

Substituting this value in equation (ii), we obtain

3x+10=4
x=-2
Hence, x=-2,y=5

Cross multiplication method

8x + 5y = 9 … (1)

3x + 2y = 4 … (2)

⇒

⇒

⇒

⇒

⇒ x = −2 and y = 5