1. number
  2. number
  3. number
  4. number

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(i)number

= 3 x 2 + 2 + √3 + 3√2 + √3 x √2

= 6 + 2 √3 + 3 √2 + √6

(ii)number[Therefore, (a + b) (a – b) = a2 – b2]

 = 32 - (√3)2

= 9 - 3 = 6

(iii)numberTherefore, (a + b)2 = a2 + b2 + 2ab]

= (√5)+ (√2)​+ 2 x √5 x √2

= 5 + 2 + 2 x √5 x 2

= 7+ 2√10

(iv)number[Therefore, (a + b) (a – b) = a2 – b2]

= (√5)- (√2)

= 5 -2 = 3

solved 5
wordpress 4 mins ago 5 Answer 70 views +22

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