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(i)
= 3 x 2 + 2 + √3 + 3√2 + √3 x √2
= 6 + 2 √3 + 3 √2 + √6
(ii)[Therefore, (a + b) (a – b) = a2 – b2]
= 32 - (√3)2
= 9 - 3 = 6
(iii)Therefore, (a + b)2 = a2 + b2 + 2ab]
= (√5)2 + (√2)2 + 2 x √5 x √2
= 5 + 2 + 2 x √5 x 2
= 7+ 2√10
(iv)[Therefore, (a + b) (a – b) = a2 – b2]
= (√5)2 - (√2)2
= 5 -2 = 3
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