Mention the shape and draw a diagram of XeO3.

Explanation

From VSEPR theory we can easily predict the shape of the given molecule XeO3.

Central atom is Xe and 3 O is side atoms.

Balance electron of Xe is 8.

And oxygen (O) is divalent atom.

Compound is neutral.

Hybridization number =1/2× [number of valence electrons of the central atom +number of monovalent atom+positive charge on the molecule - negative charge on the molecule]

For XeO3 Hybridization number

= 1/2× [8+0+0-0] = 1/2×8 =4

Hybridization number 4 implies that the molecule is Sp3 hybridized. Therefore the geometry of the molecule is tetrahedral.

Now lone pairs present on the central atom have a drastic effect on the shape of the molecule.

Number of lone pair =1/2× [Number of valence electrons - Number of bond pair electrons ( i.e no of side atom )] = ½(8- 6) = 2/2 = 1lone pair

Now applying VSEPR rules, we have to place this lone pair in maximum distance to minimise the repulsions,in tetrahedral geometry.So, the actual shape of the molecule becomes trigonal pyramidal.

Final answer

Shape of the molecules is Trigonal pyramidal.