(i) Sin A Cos C + Cos A Sin C (ii) Cos A Cos C – Sin A Sin C Report Question If BC is k, then AB will be, where k is a positive integer In ΔABC, AC2 = AB2 + BC2 = 3k2 + k2 = 4k2 AC = 2k (i) sin A cos C + cos A sin C (ii) cos A cos C - sin A sin C = 0 solved 5 wordpress 4 mins ago 5 Answer 70 views +22
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