AC2= AB2+BC2+2BC.BD Report Question Using Pythagoras theorem in ΔADB, we get: AB2 = AD2 + DB2 (i) Applying Pythagoras theorem in ΔACD, we obtain AC2 = AD2 + DC2 AC2 = AD2 + (DB + BC)2 AC2 = AD2 + DB2 + BC2 + 2DB x BC AC2 = AB2 + BC2+ 2DB x BC [Using equation (i)] solved 5 wordpress 4 mins ago 5 Answer 70 views +22
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