If AD ⊥ BC and EF ⊥ AC,prove that Δ ABD ~ Δ ECF Report Question Given that ABC is an isosceles triangle AB = AC ⇒∠ABD = ∠ECF In ΔABD and ΔECF, ∠ADB = ∠EFC (Each 90°) ∠BAD = ∠CEF (Proved above) ΔABD ~ΔECF (By using AA similarity criterion) solved 5 wordpress 4 mins ago 5 Answer 70 views +22
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