Report Question : It is given in the question that ΔABE ≅ ΔACD ∴ AB = AC (By CPCT) (i) And, AD = AE (By CPCT) (ii) In ΔADE and ΔABC, Dividing equation (ii) by (i) ∠A = ∠A (Common) Hence, ΔADE~ ΔABC (By SAS similarity) solved 5 wordpress 4 mins ago 5 Answer 70 views +22
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