If g is acceleration due to gravity on the earth's surface, the gain in the potential energy of an object of mass m raised from the surface of earth to a height equal to the radius R of the earth is

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Explanation:

The total potential energy gained 

ΔU=U2-U1

⇒ΔU=((-GMm)/2R)-(-GMm/R)

⇒ΔU=GMm/2R

As we know g=GM/R2

⇒ΔU=1/2 mgR.

As we know g=GM/R^2 

⇒ΔU=1/2 mgR.

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