If evaluate

Let us consider a right triangle ABC, right-angled at point B

=7/8  If BC is 7k, then AB will be 8k, where k is a positive integer.

Applying Pythagoras theorem in ΔABC, we obtain

AC² = AB² + BC²

= (8k)² + (7k)²

= 64k² + 49k²

= 113k²

(ii) Cot² θ = (cot θ)²