If AD and PM are medians of triangles ABC and PQR, respectively whereΔ ABC ~ Δ PQR,

 It is given that ΔABC is similar to  ΔPQR

We know that the corresponding sides of similar triangles are in proportion

Also, ∠A = ∠P

∠B = ∠Q

∠C = ∠R    (ii)

Since AD and PM are medians, they divide their opposite sides

BD = BC/2 and,

QM =  QR/2    (iii)

From (i) and (iii), we get

(iv)

In ΔABD and ΔPQM,

∠B = ∠Q [Using (ii)]

    [Using (iv)]

ΔABD ~ ΔPQM (By SAS similarity)