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Let (1, 2), (4, y), (x, 6), and (3, 5) are the coordinates of A, B, C, D vertices of a parallelogram ABCD.

 Intersectionpoint O of diagonal AC and BD also divides these diagonals.

Therefore, O is the mid-point of AC and BD

Geometry

If O is the mid-point of AC, then the coordinates of O are:

Geometry

If O is the mid-point of BD, then the coordinates of O are:

Geometry

Since both the coordinates are of the same point O

Geometry

x + 1 = 7

x = 6

And,

 Geometry

5 + y = 8

y = 3

 

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wordpress 4 mins ago 5 Answer 70 views +22

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