If 0.5 moles of BaCl2 is mixed with 0.20 moles of Na3PO4

Explanation:

Complete balanced equation for reaction between BaCI₂ and Na₃PO₄ is

3 BaCl₂ + 2Na₃PO₄ → 6 NaCl + Ba₃ (PO₄)₂ Given, 0.5 mol of BaCl₂ and 0.2 mol of Na₃PO₄, are mixed.

It is clear from the above equation that for 3 moles Of BaCl₂, 2 moles of Na₃PO₄ is required

Thus, according to the given amounts, it can be said that Na₃PO₄ is the limiting reagent.

So, to find moles of Ba₃(PO₄)₂, we must compare with the moles of Na₃PO₄.

2 mol of Na₃PO₄ ⇒ 1 mol f Ba₃(PO­₄)₂

Thus, 0.2 mol of Na₃PO₄ ⇒ 0.1 mol f Ba₃(PO­₄)₂

Final Answer:

Hence, the correct option is A: 0.1