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Since, 100 is the smallest three digit number and it gives a reminder of 2 when divided by 7, therefore, 105 is the smallest three digit number which is divisible by 7.
Since, 999 is greatest three digit number, and it gives a reminder of 5, thus 999 – 5 = 994 will be the greatest three digit number which is divisible by 7.
Therefore, here we have,
First term (a) = 105,
The last term (an) = 994
The common difference = 7
We know that, an = a + (n – 1)d
Or, 994 = 105 + (n – 1)7
Or, (n – 1)7 = 994 – 105 = 889
Or, n – 1 = 127
Or, n = 128
Thus, there are 128 three digit numbers which are divisible by 7.
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