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The formulae of calculating the percentage of Fe is 0.33 % molecular weight of hemoglobin
Weight of Fe present = 0.33/100 × 67200 = 221.8
One Fe weighs 55.8 g
Thus, the number of atoms in one molecule of hemoglobin is 221.8/55.8 =4
Final Answer: Hence, the correct answer is (B) 4.
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