Share
Report
Question
Consider a right-angled triangle, right-angled at B
It is given that,
Let AB be 8k.Therefore, BC will be 15k, where k is a positive integer.
Applying Pythagoras theorem in ΔABC, we obtain
AC2 = AB2 + BC2
= (8k)2 + (15k)2
= 64k2 + 225k2
= 289k2
AC = 17k
solved
5
wordpress
4 mins ago
5 Answer
70 views
+22
Leave a reply