Find the sum of the following APs

(i)       2, 7, 12, . . ., to 10 terms.

           (ii) –37, –33, –29, . . ., to 12 terms.

           (iii) 0.6, 1.7, 2.8, . . ., to 100 terms.

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Question

(i) Here, a = 2, d = 5 and n = 10

Sum of n terms can be given as follows:

Arithmetic

Thus, sum of the 10 terms of given AP (S_n)=245

(ii) Here, a = - 37, d = 4 and n = 12

Sum of n terms can be given as follows:

Arithmetic

Thus, sum of the 12 terms of given AP (S_n)= -180

(iii) Here, a = 0.6, d = 1.1 and n = 100

Sum of n terms can be given as follows:

Arithmetic

Thus, sum of the 100 terms of given AP (S_n)= -5505

(iv) Here,

a= 1/15, n = 11,

d =1/12-1/15=1/60

Sum of n terms can be given as follows:

Arithmetic

Thus, sum of the 100 terms of given AP (S_n)=33/20

solved 5

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