(i)       PE = 3.9 cm, EQ = 3 cm, PF = 3.6 cm and FR = 2.4 cm

           (ii)  PE = 4 cm, QE = 4.5 cm, PF = 8 cm and RF = 9 cm

           (iii) PQ = 1.28 cm, PR = 2.56 cm, PE = 0.18 cm and PF = 0.36 cm

 

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(i) Given : PE = 3.9 cm,

EQ = 3 cm,

PF = 3.6 cm,

FR = 2.4 cm

Now,

Traingles

Therefore, EF is not parallel to QR

(ii) In this,

Triangles

Hence,

EF is parallel to QR

 

 

 

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