Draw the graphs of the equations x – y + 1 = 0 and 3x + 2y – 12 = 0.

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Determine the coordinates of the vertices of the triangle formed by these lines and the x-axis, and shade the triangular region.

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For equation x – y + 1 = 0, we have following points which lie on the line

x - y + 1 = 0
x = y – 1

x	0	1	2
y	1	2	3

For equation 3x + 2y – 12 = 0, we have following points which lie on the line

variable

x	4	2	0
y	0	3	6

variable

We can see from the graphs that points of intersection of the lines with the x–axis are (–1, 0), (2, 3) and (4, 0).

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