Density of a 2.05 M solution of acetic acid in water is 1.02 g/ml. The molality of the solution is:

Explanation:

Mass of 1 L solution of 2.05 M acetic acid =1.02g/ml x1000ml=1020 g

Mass of solute in solution

=2.05 mol/Lx60g/mol=123g/ L,

where molar mass of acetic acid 60g/ mol

Mass of solvent in 1 L solution=1020-123=897g

Molality of the solutions

=(2.05x1000)/(897)= 2.28 mol kg^-1

Final answer:

(C) 2.28 mol kg^-1