Crystal field stabilization energy for high spin d4 octahedral complex is

Explanation:

The correct answer is option D which can be elaborated as follows:

Crystal field stabilization energy for an octahedral complex is given by the formula:

CFSE = (0.6 x n_eg - 0.4 x n_t2g) ∆₀

In general, splitting of octahedral complex is shown as follows:

Since given octahedral complex is high spin d⁴, so 3 electrons occupy t_2g and 1 electron occupies e_g.

This splitting of high spin d⁴ can be diagrammatically shown as follows:

Therefore, CFSE of given complex is calculated as follows:

(0.6 x 1-0.4x 3) ∆₀

= -0. 6∆₀

Final Answer:

The crystal field stabilization energy (CFSE) of given high spin d⁴ is determined to be -0. 6 ∆₀, so the correct answer is option D.