Calculate the shortest and longest wavelengths of Balmer series of hydrogen atom.

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Calculate the shortest and longest wavelengths of Balmer series of hydrogen atom. Given R = 1.097 × 10⁷m^-1R.

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Explanation:

The smallest wavelength in the Balmer series is calculated using

smallest wavelength in the Balmer

The largest wavelength in the Balmer series is calculated using smallest wavelength in the Balmer series is calculated

smallest wavelength in the Balmer

Final Answer:

Hence, the shortest wavelength is 364.6 nm and largest wavelength is 656.3nm.

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