Calculate the number of atoms of each element present in 122.5 g of KCIO3.

The number of atoms of each element present in given mass of KClO₃ can be calculated by initially determining the number of moles of KClO₃ and proceeding as follows:

Molar mass of KClO₃=39 ×1 + 35.5 × 1 + 16 × 3 = 122.5

Where 39=At.mass of K, 35.5=at.mass of Cl and 16=at.mass of O.

So, no.of moles of KClO₃= (Given mass of KclO₃)/(Molar mass of KClO₃ )=122.5/122.5 =1

As it can be observed from the chemical formula, 1 mole of KClO₃ contains 1 mole atoms of K and Cl each and 3 mole atoms of O.

Since 1 mole contains N_A particles i.e.6.022 x10²³

Hence, the number of atoms of each element present in 122.5g i.e. 1 mole of KClO₃ is:

1 mole or 6.022 x10²³ atoms of potassium (K) and chlorine(Cl) each &

3 moles or 18.066 x 10²³ oxygen atoms.