Balance the following equations: C2H6 + O2 → CO2+H2O

Let's start with reactants.

The number of carbons in the atmosphere is not the same as the number of carbons in products.

There are two carbon atoms on the reactant side and one carbon atom on the product side.

To balance, we must multiply by 2.

LHS contains six hydrogen atoms, whereas RHS contains two hydrogen atoms.

We can balance the hydrogen atoms by multiplying by 3.

The equation now reads:

C₂H₆ + O₂ → 2CO₂+ 3H₂O

LHS has two oxygen atoms and RHS has seven oxygen atoms.

To balance the oxygen atom, we can multiply by 7/2.

The equation is now:

C₂H₆ + 7/2O₂ → 2CO₂+ 3H₂O

However, it is assumed that coefficients are whole numbers.

So we get the balanced chemical equation by multiplying the entire equation by 2.

2C₂H₆ +7O₂ → 4CO₂+ 6H₂O

Final Answer: The balanced equation of C₂H₆ + O₂ → CO₂+H₂O is  2C₂H₆ +7O₂ → 4CO₂+6H₂O