(i) Δ APB ≅Δ CQD (ii) AP = CQ Report Question (i) In ΔAPB and ΔCQD, ∠APB = ∠CQD (Each 90°) AB = CD (Opposite sides of parallelogram ABCD) ∠ABP= ∠CDQ (Alternate interior angles for AB || CD) ΔAPB ≅ ΔCQD (By AAS congruency) (ii) By using the above result ΔAPB ≅ΔCQD, we obtain AP = CQ (By CPCT) solved 5 wordpress 4 mins ago 5 Answer 70 views +22
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