If the train would have been 10 km/h faster, it would have taken 2 hours less than the scheduled time. And, if the train were slower by 10 km/h, it would have taken 3 hours more than the scheduled time. Find the distance covered by the train.

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Let the speed of the train be x km/h and the time taken by train to travel the given distance be t hours and the distance to travel be d km.

We know that, Speed = NCERT Solutions/image004.png

x =NCERT Solutions/image003.png

Or, d = xt (i)

Using the information given in the question, we obtain

(x + 10) =NCERT Solutions/image003.png

(x+10) (t-2) = d

Xt+10t-2x-20 = d

By using equation (i),

we obtain - 2x + 10t = 20 (ii)

(x-10) =NCERT Solutions /image007.png

(x-10) (t+3) = d

Xt-10t+3x-30 = d

By using equation (i), we

obtain 3x - 10t = 30 (iii)

Adding equations (ii) and (iii),

we obtain x = 50

 

Using equation (ii), we

obtain ( - 2) × (50) + 10t = 20

- 100 + 10t =

10t = 120

t = 12 hours

From equation (i), we obtain

Distance to travel = d = xt

= 50 × 12

= 600 km

Hence, the distance covered by the train is 600 km.

 

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