A stone is thrown in vertically upward direction with a velocity of 5 ms

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A stone is thrown in vertically upward direction with a velocity of 5 ms . If the acceleration of the stone during its motion is 5 ms2 in the downward direction, what will be the height attained by the stone and how much time will it take to reach there?

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Given, initial velocity, u = 5ms^-1

Final velocity, v = 0

Therefore, a = -10ms^-2/

Height attained by stone, s = ?

Time take to attain height, t = ?

(i) Using the relation,

v² - u²= 2as

s = v²– u²/2a

(0) – (5)²/2 x (-10) = 1.25m

(ii) Using the relation,

v = u + at

⇒ t = 5/10

⇒ t = 0.5s

Hence, option A is correct

solved 5

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